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3 August, 05:24

To what volume should 5.0 g of KCl be diluted in order to prepare a 0.15 M solution? L

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  1. 3 August, 07:30
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    Answer:0.45L

    Explanation:

    molarity=0.15M

    Mass=5g

    No of moles=mass ➗ molecular mass

    Molecular mass of KCL=39.0983x1+35.453x1

    Molecular mass of KCL=74.5513

    No of moles=5 ➗ 74.5513

    No of moles=0.067

    Volume in liters=No of moles ➗ molarity

    Volume in liters=0.067 ➗ 0.15

    Volume in liters=0.45L
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