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26 July, 18:51

Consider the reaction between barium chloride and sodium sulphate. If 25.0 mL of 0.75 M barium chloride react, how many grams of solid are produced?

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  1. 26 July, 20:09
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    C=n/v = > n=CxV (convert V=25ml=0.025L)

    n=0.75x0.025 = 0.01875

    m=n/M

    m = 0.01875 / (108+35.5x2) = 3.35625g

    I'm pretty sure that's the way to solve it but the answer is pretty small that kinda make me uncomfortable
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