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2 June, 10:29

What is the concentration of a base with a pOH of 12?

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Answers (1)
  1. 2 June, 10:38
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    Answer: 1 x 10^-12 M

    Explanation:

    pOH is the negative logarithm of hydroxide ion concentration in a base.

    Mathematically, pOH is expressed as

    pOH = - log (OH-)

    where OH - is hydroxide ion concentration

    So, 12 = - log (OH-)

    (OH-) = Antilog (-12)

    (OH-) = 1 x 10^-12 M

    Thus, the concentration of the base is 1 x 10^-12 M
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