What pressure in mmHg is required to contain 0.02300 mol of nitrogen gas in a 4.200 L container at a temperature of 21.00°C? Round to the nearest tenths place.

Answer: 100.3 mmHg

Explanation:

Given that:

Volume of nitrogen gas V = 4.200 L

Temperature T = 21°C

Convert Celsius to Kelvin

(21°C + 273 = 294K)

Pressure P = ?

Number of moles of gas = 0.02300

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 4.200L = 0.02300 moles x (0.0821 atm L K-1 mol-1 x 294K)

p x 4.200L = 0.555 atm L

p = 0.555 atm L / 4.200L

p = 0.132 atm

Now, convert pressure in atm to mmHg

If 1 atm = 760 mmHg

0.132 atm = (0.132 x 760) = 100.3 mmHg

Thus, 100.3 mmHg of pressure is required