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9 June, 04:28

What is the mass of 2.56 * 10-4 moles of Fe2O3? : 6.23 * 105 159.6 g 1.60 * 0-6 g 4.09 * 10-2 g

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  1. 9 June, 06:57
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    4.09 * 10⁻² g

    Solution:

    As we know that,

    1 mol of Fe₂O₃ is equal to = 159.69 g

    So,

    2.56 * 10⁻⁴ mol will be equal to = X g

    Solving for X,

    X = (159.69 g * 2.56 * 10⁻⁴ mol) : 1 mol

    X = 0.04088 g

    Or,

    X = 0.049 g

    Or,

    X = 4.09 * 10⁻² g
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