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7 February, 18:34

What volume of a 0.12 m koh solution is needed to react with 23. ml of 0.22 m hcl? the reaction is: koh (aq) + hcl (aq) → kcl (aq) + h2o (l) ?

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Answers (2)
  1. 7 February, 19:41
    0
    42.17 mL

    Explanation:

    Step 1:

    The balanced equation for the reaction. This is illustrated below:

    KOH + HCl - > KCl + H2O

    From the balanced equation above, the following were obtained:

    Mole of the acid (nA) = 1

    Mole of the base (nB) = 1

    Step 2:

    Data obtained from the question. This includes:

    Molarity of the base (Mb) = 0.12 M

    Volume of the base (Vb) = ?

    Volume of the acid (Va) = 23 mL

    Molarity of the acid (Ma) = 0.22 M

    Step 3:

    Determination of the volume of the base.

    Applying the equation:

    MaVa/MbVb = nA/nB

    The volume of the base can be obtained as illustrated below:

    MaVa/MbVb = nA/nB

    0.22 x 23 / 0.12 x Vb = 1

    Cross multiply to express in linear form.

    0.12 x Vb = 0.22 x 23

    Divide both side by 0.12

    Vb = (0.22 x 23) / 0.12

    Vb = 42.17 mL

    Therefore, 42.17 mL of 0.12M KOH solution is needed to react with 23 ml of 0.22 M HCl.
  2. 7 February, 20:17
    0
    The question is formatted wrong. The correct question should be

    What volume of a 0.12 M KOH solution is needed to react with 23 ml of 0.22 M HCl? the reaction is: KOH (aq) + HCl (aq) → KCl (aq) + H2O (l) ?

    Answer:-

    42.2 mL

    Explanation:-

    Strength of HCl = 0.22 M

    Volume of HCl = 23 mL = 23 / 1000 L = 0.023L

    Number of moles of HCl = strength x volume

    = 0.22 M x 0.023 L

    = 0.00506 moles

    According to the chemical equation

    KOH (aq) + HCl (aq) → KCl (aq) + H2O (l)

    1 mol of HCl reacts with 1 mol of KOH

    0.00506 moles of HCl reacts with 0.00506 moles of KOH

    Strength of KOH = 0.12 M

    Volume of KOH = Number of moles / Strength

    = 0.00506 moles / 0.12 M

    = 0.0422 L

    = 42.2 mL
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