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30 July, 13:45

The concentration of SO32 - in a solution is determined by titration with a 0.1355 M permanganate solution. The balanced net ionic equation for the reaction is: 2MnO4 - (aq) + 5SO32 - (aq) + 6H3O + (aq) 2Mn2 + (aq) + 5SO42 - (aq) + 9H2O (l) (a) If 23.89 mL of the 0.1355 M permanganate solution are needed to react completely with 25.00 mL of the SO32 - solution, what is the concentration of the SO32 - solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Mn2 + ion is transferred to a volumetric flask and diluted to 400. mL. What is the concentration of Mn2 + in the diluted solution? M

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  1. 30 July, 17:16
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    a) 0.3237M of the SO₃⁻ solution.

    b) Permanganate solution

    c) 0.008093M

    Explanation:

    a) Based in the reaction, 2 moles of MnO₄⁻ react with 5 moles of SO₃⁻. Moles of permanganate used in titration are:

    0.02389L*0.1355mol/L = 0.003237moles of MnO₄⁻. The moles of SO₃⁻ are:

    0.003237moles of MnO₄⁻ * (5 moles of SO₃⁻ / 2 moles of MnO₄⁻) = 0.008093 moles of SO₃⁻

    As volume of the solution is 25.00mL, the concentration of the solution is:

    0.008093 moles of SO₃⁻ / 0.02500L = 0.3237M of the SO₃⁻ solution.

    b) In a titration, the solution that is in the buret (Titrant), is the solution of known concentration, for the problem, permanganate solution

    c) The moles of the Mn²⁺ solution are the same of MnO₄⁻. That is:

    0.003237moles. As the volume of the new solution is 400mL, the concentration of the solution is:

    [ Mn²⁺] = 0.003237moles / 0.400L = 0.008093M
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