A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm, what was the volume of the sample

0.0613 L

Explanation:

Given data

Initial pressure (P₁) : 1.00 atm Initial volume (V₁) : 1.84 L Final pressure (P₂) : 30.0 atm Final volume (V₂) : ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ * V₁ = P₂ * V₂

V₂ = P₁ * V₁ / P₂

V₂ = 1.00 atm * 1.84 L / 30.0 atm

V₂ = 0.0613 L