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14 January, 06:38

What mass of H₂O is formed when excess H₂ reacts with 64 g of O₂? *

2H2+O2 - ->2H2O

Answer: 72g

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Answers (1)
  1. 14 January, 07:15
    0
    72g of H2O.

    Explanation:

    We'll begin by writing the balanced equation for the reaction. This is given below:

    2H2 + O2 - >2H2O

    Next, we'll determine the mass of O2 that reacted and the mass of H2O produced from the balanced equation.

    This is illustrated below:

    Molar Mass of O2 = 16x2 = 32g/mol

    Molar Mass of H2O = (2x1) + 16 = 18g/mol

    Mass of H2O from the balanced equation = 2 x 18 = 36g

    Summary:

    From the balanced equation above,

    32g of O2 reacted to produce 36g of H2O.

    Now, we can obtain the mass of H2O produced when 64g of O2 react as follow:

    From the balanced equation above,

    32g of O2 reacted to produce 36g of H2O.

    Therefore, 64g of O2 will react to produce = (64 x 36) / 32 = 72g of H2O.

    From the calculations made above, 72g of H2O is produced from the reaction.
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