Calcium reacts with sulfur forming calcium sulfide. what is the theoretical yield (g) of cas (s) that could be prepared from 1.6 g of ca (s) and 4.25 g of sulfur (s) ? enter your answer with two decimal places. do not type units with your answer.

The balanced equation for the above reaction is;

Ca + S - - - > CaS

stoichiometry of Ca to S is 1:1

Number of Ca moles - 1.6 g / 40 g/mol = 0.04 mol

Number of S moles - 4.25 g / 32 g/mol = 0.13 mol

since Ca to S molar ratio is 1:1, there's excess amount of S present.

Ca is the limiting reactant.

stoichiometry of Ca to CaS is 1:1

Number of CaS moles to be formed - 0.04 mol

Therefore mass of CaS - 0.04 mol x 72 g/mol = 2.88 g

therefore theoretical yield is 2.88