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27 February, 10:30

Calculate the ionization energy of doubly ionized lithium, li2+, which has z=3.

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  1. 27 February, 11:39
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    Answer: I'm assuming the question is asking when it "jumps" from level 2 to level 1. In which case: 1/Î" = Rh (1/nf^2 - 1/nfi^2) = 1.10x10^7 (1/1^2 - 1/2^2) = 1.10x10^7 (1 - 0.25) = 1.10 x10^7 (0.75) Î" = 1.21 x 10^-7 m The wavelength produced will be about 1.21 x 10^ - 7 m, or 121 nm.
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