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4 September, 10:55

Estimate the heat of neutralization of H3PO4 in kJ/mol given these dаta: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 10-3 mol Moles of NaOH = 5.0 x 10-3 mol

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  1. 4 September, 11:25
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    1.) write out the balance equation 3NaOh+H3PO4->Na3PO4+3H2O

    2.) You are given everything needed to calculate q=heat transfer=2.2*10^2, H3PO4 moles = 1.5*10^-3, NaOH moles=5.0*10^-3

    3.) equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first

    4.) Now plug in variables DeltaH=2.2*10^2 (1.5*10^3) = 146.67kj/mole Notice we had to convert J to kj,
  2. 4 September, 11:46
    0
    write out the balance equation

    3NaOh+H3PO4->Na3PO4+3H2O

    You are given everything needed to calculate

    q=heat transfer=2.2*10^2,

    H3PO4 moles = 1.5*10^-3,

    NaOH moles=5.0*10^-3

    equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first

    Now plug in variables

    DeltaH=2.2*10^2 (1.5*10^3) = 146.67kj/mole

    Notice we had to convert J to kj,
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