Determine the number of phosphorus atoms present in 9.20 mol of copper (II) phosphate.

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Chemistry

Milagros Avila

29 October, 12:12

Determine the number of phosphorus atoms present in 9.20 mol of copper (II) phosphate.

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Cesar Stafford · Answer 1

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles or vice versa.

9.20 mol Cu3 (PO4) 2 (2 mol P / 1 mol Cu3 (PO4) 2) (6.022 x 10^23 atoms / mole P) = 1.11 x 10^25 atoms