If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm, what is its kelvin temperature?

To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

PV = nRT

or T = PV / nR

So calculating:

T = [6.6 atm * 0.40 L] / [ (2.4g / 28g/mol) * 0.08205746 L atm / mol K]

T = 375.35 K