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15 March, 05:07

If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm, what is its kelvin temperature?

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  1. 15 March, 05:52
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    To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

    PV = nRT

    or T = PV / nR

    So calculating:

    T = [6.6 atm * 0.40 L] / [ (2.4g / 28g/mol) * 0.08205746 L atm / mol K]

    T = 375.35 K
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