Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?

Question

Chemistry

Jaxson Koch

27 October, 07:58

Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?

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Answers (1)

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Zoey Ware · Answer 1

We first calculate the decay constant, λ

λ = ln (2) / half life

λ = ln (2) / 14.3

The decay equation is:

N = N (initial) x exp (-λt)

N = 4 x exp (-ln (2) / 14.3 x 71.5)

N = 0.125 mg will remain