What is the equilibrium constant of pure water at 25°C? 1014 10-14 10-7 107

Question

Chemistry

Ignacio Curtis

3 November, 15:28

What is the equilibrium constant of pure water at 25°C? 1014 10-14 10-7 107

+2

Answers (1)

Know the Answer?

Fern · Answer 1

Pure water at standard conditions has equal number of H + and OH - ions which makes it a neutral substance with pH 7. We can solve this problem as follows:

pH = - log [H+]

7 = - log [H+]

[H+] = 10^-7 = [OH-]

K = [H+][OH-] = 10^-7 (10^-7) = 10^-14