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9 January, 17:29

What mass (g) of nan3 is required to provide 26.5 l of n2 at 22.0 °c and 1.10 atm?

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  1. 9 January, 21:13
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    NaN₃ (sodium azide) produces N₂ gas when it is heated. The balanced equation is,

    2NaN₃ → 2Na + 3N₂

    To find out mass of NaN₃, we have to find the moles of N₂ formed by using given data.

    Let's assume that N₂ gas is an ideal gas. Then we can use ideal gas equation,

    PV = nRT

    Where,

    P = Pressure of the gas (Pa)

    V = volume of the gas (m³)

    n = number of moles (mol)

    R = Universal gas constant (8.314 J mol⁻¹ K⁻¹)

    T = temperature in Kelvin (K)

    The given data for N₂ gas is,

    P = 1.10 atm = 111457.5 Pa

    V = 26.5 L = 26.5 x 10⁻³ m³

    T = (273 + 22) K = 295 K

    R = 8.314 J mol⁻¹ K⁻¹

    n = ?

    By applying the formula,

    111457.5 Pa x 26.5 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 295 K

    n = 1.204 mol

    Hence, produced N₂ gas = 1.204 mol

    The stoichiometric ratio between NaN₃ and N₂ is 2 : 3

    hence moles of NaN₃ = 1.204 mol x 2 / 3

    = 0.803 mol

    Molar mass of NaN₃ = 65 g/mol

    Hence, required mass of NaN₃ = 0.803 mol x 65 g/mol

    = 52.195 g
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