For the reaction 2Na (s) + Cl2 (g) - - > 2NaCl (s), how many grams of NaCl could be produced from 20 L of Cl2 (at STP) ?

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Chemistry

Case Chapman

10 April, 17:37

For the reaction 2Na (s) + Cl2 (g) - - > 2NaCl (s), how many grams of NaCl could be produced from 20 L of Cl2 (at STP) ?

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Semaj · Answer 1

13.0 L Cl2 * 1 mol Cl2 / 22.4 L Cl2 = 0.580 mol Cl2 103.0 g Na * 1 mol Na/23 g Na = 4.48 mol Na Cl 2 is limiting reagent: 0.580 mol Cl2 * 2 mol NaCl/1 mol Cl2 = 1.16 mol NaCl 1.16 mol NaCl * 58 g NaCl/1 mol NaCl = 67.3 g NaCl DIF: L3 REF: p. 371 OBJ: 12.3.1