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26 May, 11:36

What's the empirical formula of 36.48% Na 25.41% S 38.11% O

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  1. 26 May, 13:32
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    A compound is found to contain 36.48% Na, 25.41% S, and 38.11% O. find its empirical formula. % in such problems are by weight, & can be changed to grams out of a 100 grams total using molar mass, find moles:

    36.48g Na @ 23 g/mol = 1.6 moles

    Na 25.41g S, @ 32 g/mole = 0.8 mol

    S 38.11g O. @ 16 g/mol = 2.4 mol

    O ratio the moles, by dividing all by the smallest: 1.6 mol Na / 0.8 = 2 mol Na 0.8 mol S / 0.8 = 1 mole

    S 2.4 mol O / 0.8 = 3 mol O

    your empirical formula os Na2SO3

    It was hard when I took chemistry too! I passed with a B
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