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4 July, 04:22

Gaseous C2H4 reacts with O2 according to the following equation:

C2H4 (g) + 302 - > 2CO2 + H2O (g)

What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?

A) 17.3 L

B) 42.9 L

C) 3.86 x 10^2 L

D) 1.29 x 10^2 L

E) Not enough information is given to solve the problem.

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Answers (1)
  1. 4 July, 07:08
    0
    Each mole of C₂H₄ requires 3 moles of O₂ to react.

    5.75 moles of C₂H₄ will require:

    3 x 5.75 = 17.25 moles

    Each mole of gas occupies 22.4 L at STP.

    Liters of gas = 17.25 x 22.4

    = 3.86 x 10² L

    The answer is C.
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