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21 August, 01:48

If 0.66 g magnesium reacts exactly with 0.43 g oxygen, what mass of magnesium oxide will be produced?

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  1. 21 August, 03:03
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    Balanced equation for the reaction is;

    2Mg + O₂ - - > 2MgO

    stoichiometry of Mg to O₂ is 2:1

    we need to first find the limiting reactant

    number of Mg moles - 0.66 g / 23 g/mol = 0.029 mol

    number of O₂ moles - 0.43 g / 32 g/mol = 0.013 mol

    If Mg is the limiting reactant

    2 mol of Mg reacts with 1 mol of O₂

    then 0.029 mol of Mg reacts with - 0.029/2 = 0.0145 mol

    but only 0.013 mol of O₂ is present

    therefore O₂ is limiting reactant. amount of product formed depends on amount of limiting reactant present,

    stoichiometry of O₂ to MgO is 1:2

    when 0.013 mol of O₂ reacts - 0.026 mol of MgO is formed

    mass of MgO produced is - 0.026 mol x 39 g/mol = 1.014 g

    1.014 g of MgO formed
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