Given the enthalpies of reaction below, determine the enthalpy change for the reaction: N2O (g) + NO2 (g) 3NO (g). N2 (g) + O2 (g) 2NO (g) ΔH = + 180.7 kJ 2NO (g) + O2 (g) 2NO2 (g) ΔH = - 113.1 kJ 2N2O (g) 2N2 (g) + O2 (g) ΔH = - 163.2 kJ A. 155.6 kJ B. 130.6 kJ C. 311.3 kJ D. 65.3 kJ

Question

Chemistry

Tyrell Arnold

26 March, 21:44

Given the enthalpies of reaction below, determine the enthalpy change for the reaction: N2O (g) + NO2 (g) 3NO (g). N2 (g) + O2 (g) 2NO (g) ΔH = + 180.7 kJ 2NO (g) + O2 (g) 2NO2 (g) ΔH = - 113.1 kJ 2N2O (g) 2N2 (g) + O2 (g) ΔH = - 163.2 kJ A. 155.6 kJ B. 130.6 kJ C. 311.3 kJ D. 65.3 kJ

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Rebecca · Answer 1

This problem applies Hess' Law to come up with the final reaction from a series of reactions given. Equation (1) stays as it is. Equation (2) should be inverted and divided by 2. Equation (3) is simply divided by 2. The energies should also correspond to the operations. Adding the net energies of each reaction, the total energy is 155.65 kJ. Hence, the answer is A.