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8 November, 19:37

What is the equilibrium constant for the following reaction?

2A+3B 2C + D

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  1. 8 November, 20:41
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    I'm just guessing here, but from what I've seen on similar problems

    2A + 3B ↔ 2C + D

    The terms in the right will be the numerator and the terms in the left will be the denominator. The coefficient becomes the exponent.

    Kc = [C]² [D] / [A]² [B]³
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