A stock solution of naoh is 0.800 m. what volume of this solution (in ml) is needed to prepare 2.00 l of 0.342 m naoh?

The volume of the solution (in Ml) needed to prepare 2.00 L of 0.342 M NaOH is calculated using the below formula

M1V1 = M2V2

M1=0.800 M

V1=?

M2=0.342 m

V2 = 2.00 L

by making V1 the subject of the formula = M2V2/M1

= 2.00 L x 0.342 / 0.800 = 0.855 L stock solution is neede