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13 April, 23:43

For the process 2SO2 (g) + O2 (g) 2SO3 (g), S = - 187.9 J/K and H = - 198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use G = H - TS.

A) - 386.3 J/K

B) - 198.4 kJ/K

C) - 187.9 J/K

D) - 139.3 kJ

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  1. 13 April, 23:51
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    The process is

    2SO₂ (g) + O₂ (g) → 2SO₃ (g)

    According to Gibs free energy equation, G = H - TS

    where G = Gibs free energy which is a measure of chemical energy

    H = Enthalpy value of enthalpy given, H = - 198.4 kJ

    T = temperature in kelvins = 297 K

    S = entropy of this reaction

    which is S = - 187.9 J/K

    Entopy is already given in the question which is - 187.9 J/k
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