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23 August, 18:30

If the EMF produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amp·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field?

a. 0.27 meters

b. 2.8 meters

c. 0.020 meters

d. 3.7 meters

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Answers (2)
  1. 23 August, 18:41
    0
    The answer to your question is B
  2. 23 August, 20:21
    0
    B = 0.075 N/amp*m

    V = 4.20 m/s

    EMF = 0.88 Volts

    L = ?

    Formula = EMF = L x B x V

    Since we have EMF and we’re looking for L, the formula will now be:

    L = EMF x B x V

    Solution:

    = 0.88 x 0.075 x 4.2

    = 2.8

    The length of the wire in the magnetic field is 2.8m

    The answer is letter B.
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