Would precipitation occur when 500 mL of a 0.02M solution of AgNO3 is mixed with 500 mL of a 0.001M solution of NaCl? Show your work.

We know,

AgNO3 + NaCl ⇒ NaNO3 + AgCl (s)

The moles of Na + present:

0.5 L * 0.001 mol/L

= 5 x 10⁻⁴ mol

Moles of Ag + present:

0.5 * 0.02

= 0.01 mol

The limiting reactant is Na

Therefore, the moles of Ag reacted:

5 x 10⁻⁴

AgCl is insoluble in water; therefore, the AgCl formed will precipitate