How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem.

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Chemistry

Hurley

8 February, 06:16

How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem.

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Dario Shelton · Answer 1

pV=nRT, where p-pressure, V-volume, n - amount of moles, n - gas constant (n=0.080206) n=pV/RT The amount of moles can be found by the equation: n=m/M where m - mass, M - molar mass So the mass could be calculated as: m=n*M M (H2O) = 18 grams/mole n (H2O) = 0.98*10.2/0.08206 * (26+273) = 0.43 moles m (H2O) = 0.43*18=7.3 grams