A student has a sample of isopropanol (C3H7OH) that has a mass of 78.6 g. The molar mass of isopropanol is 60.1 g/mol. How many moles of isopropanol are contained in this sample?

Given:

mass of isopropanol = 78.6 g

molar mass = 60.1 g/mol

mol isopropanol = mass / molar mass

mol isopropanol = 78.6 g / 60.1 g/mol

mol isopropanol = 1.3078 mol

There is 1.3078 mol isopropanol in the sample.