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3 August, 13:52

How many joules of heat must be transferred to a 480-g aluminum pizza pan to raise its temperature from 22C to 234C? The specific heat of aluminum in this temperature range is 0.96 J/g•C. Show your work Q = mc (Tf-Ti)

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  1. 3 August, 17:21
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    The given formula for heat, Q=mc (Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.

    Q = mc (Tf-Ti) = 480g (0.96 J/g-C) (234-22) = 97689.6 Joules of heat
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