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7 January, 22:18

Calculate the number of moles in 21.5g of calcium carbonate

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  1. 7 January, 23:51
    0
    First you calculate the molar mass of calcium carbonate:

    CaCO3 = 40.078 + 12.0107 + 15.9994 x 3 = > 100.0869 g/mol

    therefore:

    n = mass of solute / molar mass

    n = 21.5 / 100.0869

    n = 0.214 moles
  2. 8 January, 01:12
    0
    N=m/M

    where m is the mass in g

    M is molar mass

    M=100.0869g/moles but we round it to 100

    n=21.5/100=0.215moles
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