Determine the percent ionization of a 0.230 m solution of benzoic acid.

We need the dissociation constant of benzoic acid which is 6.3x10^'5. Then using the dissociation formula, ka = x2 / (Mo - x) where Mo is the initial concentration. x is determined then. percent ionization is computed as (x/Mo) * 100%. This is then the final answer.