Ask Question
31 August, 23:29

How many mL of. 1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu

a. 250 mL

b. 26.95 mL

c. 25 mL

what do you do with the amu?

+3
Answers (1)
  1. 1 September, 01:20
    0
    The amu is a unit which means the mass per neutron, So the 74.55 means the mass per mole KCl. So the mole number of 2.330g KCl is 2.330/74.55=0.031 mol. The volume is 0.031/0.1250=0.248 L ≈ 250 mL. So the answer is a.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many mL of. 1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu a. 250 mL b. 26.95 mL c. 25 mL what do you do with the amu? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers