A certain shade of blue has a frequency of 7.02 * 1014 Hz. What is the energy of exactly one photon of this light?

The energy (E) per photon is expressed by Planck's equation: E = hf, where f is

the frequency and h is Planck's constant, experimentally determined to be

6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency

and obtain E = hf = (6.625 * 10**-34) (7.0 * 10**14) = 46.375 * 10**-20 joule

or in standard notation, E = 4.6375 * 10**-19 joule per photon.

Hope this answers your question. Sorry if I calculated wrong.