Ask Question
10 May, 09:16

7.62g of iron reacts with 8.67g of sulfur what is the percentage yield if only 8g of Fes is produced

+4
Answers (1)
  1. 10 May, 10:21
    0
    Fe + S = FeS (ratio is 1:1)

    Molar mass of FeS = 87.9107 g/mol

    (0.1364 mol Fe) x (1/1) x (87.9107 g FeS/mol) = 12.0 g FeS

    Theoretical yield = 12.0 g FeS

    If the actual yield of FeS = 8g

    Then percent yield (8 g / 12.0 g) = 0.67 = 67%
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “7.62g of iron reacts with 8.67g of sulfur what is the percentage yield if only 8g of Fes is produced ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers