What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?

12.5%

55.6%

79.8%

87.9%

Question

Chemistry

Nia Valenzuela

4 August, 09:01

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?

12.5%

55.6%

79.8%

87.9%

+1

Answers (1)

Know the Answer?

Davian · Answer 1

The percent yield is defined as:

((Actual Yield) / (Theoretical Yield)) * 100%

Plugging in our numbers we get:

(220.0 grams) / (275.6 grams) = 0.7983

Now multiply the quotient by 100%:

0.7983 * 100% = 79.83%

Closest answer is 79.8%

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?12.5%55.6%79.8%87.9%

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?

12.5%

55.6%

79.8%

87.9%