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18 September, 00:04

What is the limiting reactant when 8.4 moles of lithium react with 4.6 moles of oxygen gas?

Unbalanced equation: Li + O2 → Li2O

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  1. 18 September, 03:25
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    First balance the equation

    4Li + O2 - > 2Li2O

    then to figure the limiting reactant use the numbers in front of each reactant as a ratio

    4:2 for Li to Li2O

    1:2 for O2 to Li2O

    then use those to multiple or divide the number if moles to get the moles of Li2O it would make

    Li=8.4 and because it's 4:2 (or 2:1) then 1 mole of Li make half as many moles of Li2O.

    8.4/2 = 4.2

    O2 = 4.6 and the ratio is 1:2 meaning 1 mole of O2 makes twice as many moles of Li2O

    4.6x2 = 9.2
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