A 20.0 mL sample of a NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.

a) Mass/mass%

b) Mass/volume%

c) Molarity (M)

Question

Chemistry

Marquise Fernandez

22 May, 00:15

A 20.0 mL sample of a NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.

a) Mass/mass%

b) Mass/volume%

c) Molarity (M)

+5

Answers (1)

Know the Answer?

Corey Mullen · Answer 1

Mass NaCl = 4.348

Mass solution = 21.040 - 4.348 = 16.692

mass/mass % =

4.348/16.692

= 26%

mass/vol % =

21.7%

Molecular mass of NaCl = 58.5

Moles of NaCl = 0.074

Volume of solution = 0.02 L

Molarity = 3.7 mol/Liter

A 20.0 mL sample of a NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.a) Mass/mass%b) Mass/volume%c) Molarity (M)

A 20.0 mL sample of a NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.

a) Mass/mass%

b) Mass/volume%

c) Molarity (M)