The activation energy for the reaction no2 (g) + co (g) ⟶no (g) + co2 (g) is ea = 75 kj/mol and the change in enthalpy for the reaction is δh = - 275 kj/mol. what is the activation energy for the reverse reaction?

Answer: 350 kj/mol

Explanation:

As shown below this expression gives the activation energy of the reverse reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

1) The activation energy, EA is the difference between the potential energies of the reactants and the transition state:

EA = energy of the transition state - energy of the reactants.

2) The activation energy of the forward reaction given is:

EA = energy of the transition state - energy of [ NO2 (g) + CO (g) ] = 75 kj/mol

3) The negative enthalpy change - 275 kj / mol for the forward reaction means that the products are below in the potential energy diagram, and that the potential energy of the products, [NO (g) + CO2 (g) ] is equal to 75 kj / mol - 275 kj / mol = - 200 kj/mol

4) For the reverse reaction the reactants are [NO (g) + CO2 (g) ], and the transition state is the same than that for the forward reaction.

5) The difference of energy between the transition state and the potential energy of [NO (g) + CO2 (g) ] will be the absolute value of the change of enthalpy plus the activation energy for the forward reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

EA reverse reaction = 75 kj / mol + |-275 kj/mol | = 75 kj/mol + 275 kj/mol = 350 kj/mol.

And that is the answer, 350 kj/mol