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30 June, 09:39

A gas occupies 3.60 L when the temperature is 45.0oC and at 1.02 atm of pressure. What temperature change (in K) will be needed to change the volume to 6.25 L at constant pressure?

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  1. 30 June, 10:08
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    As we know V1/T1=V2/T2

    so, V1=3.60

    V2=6.25

    T1=45c=318k

    T2=required

    solution!

    T2=V2 multiply by T1/V1 so

    put the values and find your answer which should be 552k
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