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3 January, 10:46

What is the mass, in grams, of a sample of 7.83 * 1024 atoms of helium (He) ? Show your work or explain the steps that you used to determine your answer.

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  1. 3 January, 12:12
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    First, we will get the number of moles:

    one mole contains Avogadro's number of atoms. Therefore, to know the number of moles in 7.83 * 10^24 atoms, we will simply do cross multiplication as follows:

    number of moles = (7.83 * 10^24*1) / (6.022 * 10^23) = 13 moles

    From the periodic table:

    mass of one mole of helium = 4 grams

    Therefore:

    mass of 13 moles of helium = 13*4 = 52 grams
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