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17 September, 21:59

Determine the mass of sodium carbonate required to produce 23.4g of sodium chloride when it reacts with excess hydrochloric acid.

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  1. 18 September, 00:07
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    The balanced chemical reaction for the described reaction above is,

    Na2CO3 + 2HCl - - - > 2NaCl + H2CO3

    From the reaction, 1 mole of Na2CO3 is needed to produce 2 moles of NaCl. In terms of mass, 106 grams of Na2CO3 are needed to produce 116.9 grams of NaCl. From this,

    (23.4 g NaCl) x (106 g Na2CO3 / 116.9 NaCl = 21.22 g Na2CO3

    Thus, approximately 21.22 g Na2CO3 is needed for the desired reaction.
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