The heat capacity of benzene (c6h6) is 81.7 jmol-1°c-1. how much heat (in joules) is required to raise the temperature of 39.0 g of benzene by 10.0 °c?

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Chemistry

Payton Zimmerman

15 March, 23:17

The heat capacity of benzene (c6h6) is 81.7 jmol-1°c-1. how much heat (in joules) is required to raise the temperature of 39.0 g of benzene by 10.0 °c?

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Braden Huang · Answer 1

Answer is:.408,5 J. m (C₆H₆-benzene) = 39 g.

n (C₆H₆) = m (C₆H₆) / M (C₆H₆) = 39g : 78g/mol = 0,5 mol.ΔT = 10,0°C, difference at temperature. c (benzene) = 81,7 J/mol·°C, specific heat of benzene. Q = n (benzene) · ΔT · c (benzene), heat of reaction. Q = 0,5 mol · 10,0°C · 81,7 J/mol·°C. Q = 408,5 J.