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14 June, 07:58

A 2.5 g copper penny is given a charge of 4.0x10-9

c. how many electrons are removed from the penny?

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  1. 14 June, 09:00
    0
    One electron has a charge of 1.602 x 10^-19 Coulombs (C), so to calculate the total number of electrons, we divide the total charge 4.0 x 10^-9 C by the charge of a single electron. This gives us:

    4.0 x 10^-9 / 1.602 x 10^-19 = 2.5 x 10^10 electrons that are removed from the penny
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