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19 March, 16:58

Using the ideal gas equation, calculate the pressure of oxygen gas in a cylinder with a volume of 25.00 L. The oxygen masses 4.362 kg and room temperature is at 22.5 o C. How many moles of oxygen are there and what is the pressure of oxygen in atmospheres in the cylinder according to the ideal gas law?

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  1. 19 March, 20:34
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    Equation: PV=nRT

    Rearrange: P=nRT/V

    Mols of oxygen = m/M = 4362g/16g/mol

    =272.625

    P=272.625*8.314 * (22.5+273.15) / 25

    =26804 pascales

    =0.26453491Atmosphere
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