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26 January, 18:07

How many atoms are in 80.45 g of magnesium?

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  1. 26 January, 18:34
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    There are 1.993x10^24 atoms in 80.35 g of Magnesium.
  2. 26 January, 19:24
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    M (Mg) = 80.45 g

    We can find the molar mass of magnesium in the Periodic table:

    M (Mg) = 24.31 g / mole

    n = 80.45 g : 24.31 g/mole = 3.31 moles

    N a (Avogadro's constant) = 6.02 * 10 ^23

    N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^23

    Answer: There are 1.9926 * 10 ^24 atoms.
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