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8 November, 23:36

A sample of ammonia gas, NH3, has a volume of 285.0 mL at a pressure of 98.50 kPa. What will the volume of the ammonia be at a pressure of 94.20 kPa? Assume that all other properties of the gas remain constant.

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  1. 9 November, 01:32
    0
    Using Avogadro's law

    where: P1V1/n1T1 = P2V2/n2T2

    The problem states it implicitly but n and T are constant

    P1V1 = P2V2

    V2 = P1V1/P2

    P1 = 98.50 kPa

    V1 = 285.0 mL

    P2 = 94.20 kPa

    V2 = (98.50 x 285) / 94.20

    V2 = 298.00 mL

    The volume increases to 298 mL.
  2. 9 November, 02:44
    0
    We know that an ideal gas keeps the relation between pressure, volume and temperature constant.

    P * V / T = constant

    Then if we have the gas in two diferente state:

    P1*V1/T1 = P2*V2/T2

    Temperature remain constant so then:

    P1*V1 = P2*V2

    98.5*285 = 94.2*V2

    V2 = 98.5*285/94.2 = 298 ml

    So the volume of the ammonia will be 298 ml
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