Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘C.

Question

Chemistry

Pooky

8 May, 10:58

Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘C.

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Answers (1)

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Baylee Mathis · Answer 1

The latent heat of vaporization of steam is equal to its latent heat of condensation. The heat released is given by:

Q = ml

Q = 20 x 2257 joules/gram

Q = 45.14 kJ of heat is removed from the steam

1 calorie = 4.184 kJ

45.14 kJ = 10.8 cal of energy

The energy removed is 10.8 calories