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13 July, 15:17

A 25-liter sample of steam at 100°c and 1.0 atm is cooled to 25°c and expanded until the pressure is 19.71 mmhg. if no water condenses, calculate the final volume of the water vapor. 770 l 240 l 1.3 x 10-3 l 1.0 l

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  1. 13 July, 18:28
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    I will use [pV/T] in the state 1 = [pV/T] in the state 2.

    State 1:

    p = 1.0 atm

    V = 25 liter

    T = 100 + 273.15 = 373.15 K

    State 2:

    p = 19.71 mmHg * 1. atm / 760 mmHg = 0.0259atm

    V = ?

    T = 25 + 273.15 = 298.15 K

    Application of the formula

    1.0 atm * 25 liter / 373.15 k = 0.0259 atm * V / 298.15 K = >

    V = [1.0atm * 25 liter / 373.15 K]*298.15K/0.0259atm = 771 liter
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