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12 February, 14:10

Given 10.8 grams of substance Y, if the substance absorbs 231 kilojoules of energy and the specific heat of the substance is 6.55 J/g·°C, what is the change in temperature?

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  1. 12 February, 15:08
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    Q = mxcxdelta t

    or

    231 = 10.8x6.55x Delta t

    Delta t = 3.265 degrees celcius
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